Advertisements
Advertisements
Question
Factorised form of r2 – 10r + 21 is ______.
Options
(r – 1)(r – 4)
(r – 7)(r – 3)
(r – 7)(r + 3)
(r + 7)(r + 3)
Advertisements
Solution
Factorised form of r2 – 10r + 21 is (r – 7)(r – 3).
Explanation:
We have, r2 – 10r + 21
= r2 – 7r – 3r + 21
= r(r – 7) – 3(r – 7) ...[By splitting the middle term, so that the product of their numerical coefficients is equal constant term]
= (r – 7)(r – 3) ...[∵ x2 + (a + b)x + ab = (x + a)(x + b)]
APPEARS IN
RELATED QUESTIONS
For the following monomials, write its degree: 7y
Fill in the blank:
6xy2 + 9xy2 = _____.
Fill in the blank:
The addition of 5, 7xy, 6 and 3xy = _____
Find the sum of: 9x2 – 6x + 7, 5 – 4x and 6 – 3x2
Find the sum of: a2 + b2 + 2ab, 2b2 + c2 + 2bc and 4c2 -a2 + 2ac
Subtract the second expression from the first:
−2b + 2c, b + 3c
Simplify: - 2x (x + y) + x2
Simplify: `10 – {4"a" – (7 – bar ("a" - 5) - (5"a" - bar(1 + "a")))`
Factorise the following expression.
2ax2 + 4axy + 3bx2 + 2ay2 + 6bxy + 3by2
4p is the numerical coefficient of q2 in – 4pq2.
