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Question
Factorise:
x3 – 8y3 – 6x + 12y
Sum
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Solution
Given expression: x3 – 8y3 – 6x + 12y
⇒ [x3 – (8y)3] – 6(x – 2y)
⇒ [x3 – (2y)3] – 6(x – 2y)
We know that,
a3 – b3 = (a – b) (a2 + ab + b2)
Hence,
⇒ (x – 2y) (x2 + 2xy + 4y2) – 6(x – 2y)
⇒ (x – 2y) (x2 + 2xy + 4y2 – 6)
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