Question

Factorise:

x³ – 8y³ – 6x + 12y

Answer 1

Given expression: x³ – 8y³ – 6x + 12y

⇒ [x³ – (8y)³] – 6(x – 2y)

⇒ [x³ – (2y)³] – 6(x – 2y)

We know that,

a³ – b³ = (a – b) (a² + ab + b²)

Hence,

⇒ (x – 2y) (x² + 2xy + 4y²) – 6(x – 2y)

⇒ (x – 2y) (x² + 2xy + 4y² – 6)