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Factorise the following: x^4 – 20x^2y^2 + 64y^4 - Mathematics

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Question

Factorise the following:

x4 – 20x2y2 + 64y4

Sum
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Solution

Given: x4 – 20x2y2 + 64y4

Step-wise calculation:

1. Recognize the expression as a quadratic in terms of x2 and y2:

(x2)2 – 20(x2)(y2) + (8y2)2

2. Check if it can be factored as a perfect square or using the quadratic approach:

We try to write it as

(x2 – ay2)(x2 – by2)

where (a) and (b) satisfy:

a + b = 20

ab = 64

3. Solve for (a) and (b):

Factors of 64 that add to 20 are 16 and 4.

So, a = 16, b = 4.

4. Thus, the factorization becomes:

(x2 – 16y2)(x2 – 4y2).

5. Further factor using the difference of squares:

x2 – 16y2 = (x – 4y)(x + 4y)

x2 – 4y2 = (x – 2y)(x + 2y)

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Chapter 4: Factorisation - Exercise 4D [Page 87]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 4 Factorisation
Exercise 4D | Q 24. | Page 87
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