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प्रश्न
Factorise the following:
x4 – 20x2y2 + 64y4
योग
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उत्तर
Given: x4 – 20x2y2 + 64y4
Step-wise calculation:
1. Recognize the expression as a quadratic in terms of x2 and y2:
(x2)2 – 20(x2)(y2) + (8y2)2
2. Check if it can be factored as a perfect square or using the quadratic approach:
We try to write it as
(x2 – ay2)(x2 – by2)
where (a) and (b) satisfy:
a + b = 20
ab = 64
3. Solve for (a) and (b):
Factors of 64 that add to 20 are 16 and 4.
So, a = 16, b = 4.
4. Thus, the factorization becomes:
(x2 – 16y2)(x2 – 4y2).
5. Further factor using the difference of squares:
x2 – 16y2 = (x – 4y)(x + 4y)
x2 – 4y2 = (x – 2y)(x + 2y)
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