Advertisements
Advertisements
Question
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
(x + y)4 – (x – y)4
Advertisements
Solution
We have,
(x + y)4 – (x – y)4 = [(x + y2]2 – [(x – y)2]2
= [(x + y)2 + (x – y)2][(x + y)2 – (x – y2)]
= (x2 + y2 + 2xy + x2 + y2 – 2xy)(x + y + x – y)(x + y – x + y)
= (2x2 + 2y2)(2x)(2y)
= 2(x2 + y2)(2x)(2y)
= 8xy(x2 + y2)
APPEARS IN
RELATED QUESTIONS
Expand 4p2 – 25q2
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(4 – mn)(mn + 4)
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(6x + 7y)(6x – 7y)
The value of p for 512 – 492 = 100p is 2.
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x2 – 9
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/25 - 625`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
a4 – (a – b)4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 81
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
(a – b)2 – (b – c)2
