Advertisements
Advertisements
Question
Factorise the expression and divide them as directed:
(2x3 – 12x2 + 16x) ÷ (x – 2)(x – 4)
Advertisements
Solution
We have,
(2x3 – 12x2 + 16x) ÷ (x – 2)(x – 4)
= `(2x^3 - 12x^2 + 16x)/((x - 2)(x - 4))`
= `(2x(x^2 - 6x + 8))/((x - 2)(x - 4))`
= `(2x(x^2 - 4x - 2x + 8))/((x - 2)(x - 4))`
= `(2x[x(x - 4) - 2(x - 4)])/((x - 2)(x - 4))`
= `(2x(x - 4)(x - 2))/((x - 2)(x - 4))`
= 2x
APPEARS IN
RELATED QUESTIONS
Factorise the following expressions
m2 + m – 72
Factorise : 16p4 – 1
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(p + 2)(p – 2)
Using identity, find the value of (1.9) × (2.1)
Using suitable identities, evaluate the following.
(729)2 – (271)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
28ay2 – 175ax2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 81
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 625y4
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
Find the value of a, if pq2a = (4pq + 3q)2 – (4pq – 3q)2
