Advertisements
Advertisements
Question
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`1/36a^2b^2 - 16/49b^2c^2`
Advertisements
Solution
We have,
`1/36a^2b^2 - 16/49b^2c^2 = ((ab)/6)^2 - ((4bc)/7)^2`
= `((ab)/6 + (4bc)/7)((ab)/6 - (4bc)/7)`
= `b^2(a/6 + (4c)/7)(a/6 - (4c)/7)`
APPEARS IN
RELATED QUESTIONS
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
25a2 – 49b2
(5 + 20)(–20 – 5) = ?
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
Using suitable identities, evaluate the following.
(729)2 – (271)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 625
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2 - y^2/100`
Factorise the expression and divide them as directed:
(x2 – 22x + 117) ÷ (x – 13)
Factorise the expression and divide them as directed:
(2x3 – 12x2 + 16x) ÷ (x – 2)(x – 4)
Factorise the expression and divide them as directed:
(9x2 – 4) ÷ (3x + 2)
