Advertisements
Advertisements
Question
Factorise the following expression.
2ax2 + 4axy + 3bx2 + 2ay2 + 6bxy + 3by2
Sum
Advertisements
Solution
We have,
2ax2 + 4axy + 3bx2 + 2ay2 + 6bxy + 3by2
= (2ax2 + 2ay2 + 4axy) + (3bx2 + 3by2 + 6bxy)
= 2a(x2 + y2 + 2xy) + 3b(x2 + y2 + 2xy)
= (2a + 3b)(x + y)2
shaalaa.com
Is there an error in this question or solution?
Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 234]
APPEARS IN
RELATED QUESTIONS
Identify the terms, their coefficients for the following expressions.
0.3a − 0.6ab + 0.5b
Add : a + b and 2a + 3b
Simplify: 3x + [4x – (6x – 3)]
Simplify: 8 [m + 2n-p – 7 (2m -n + 3p)]
The co-efficient of ab in the term 15 abc is 15
The value of (a + b)2 + (a – b)2 is ______.
Common factor of ax2 + bx is ______.
The factorisation of 2x + 4y is ______.
Identify term and factor in the expression given below:
0.1 p2 + 0.2 q2
4p is the numerical coefficient of q2 in – 4pq2.
