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Question
Factorise the following expression.
2ax2 + 4axy + 3bx2 + 2ay2 + 6bxy + 3by2
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Solution
We have,
2ax2 + 4axy + 3bx2 + 2ay2 + 6bxy + 3by2
= (2ax2 + 2ay2 + 4axy) + (3bx2 + 3by2 + 6bxy)
= 2a(x2 + y2 + 2xy) + 3b(x2 + y2 + 2xy)
= (2a + 3b)(x + y)2
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