Advertisements
Advertisements
Question
Factorise the following by grouping the terms:
`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`
Sum
Advertisements
Solution
`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`
= `("p"^2 + 1/"p"^2 - 2) - (5"p" - 5/"p")`
= `(("p")^2 + (1/"p")^2 - 2 xx "p" xx 1/"p") - (5"p" - 5/"p")`
= `("p" - 1/"p")^2 - 5("p" - 1/"p")`
= `("p" - 1/"p")("p" - 1/"p" - 5)`.
shaalaa.com
Factorisation by Grouping
Is there an error in this question or solution?
