Advertisements
Advertisements
प्रश्न
Factorise the following by grouping the terms:
`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`
Advertisements
उत्तर
`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`
= `("p"^2 + 1/"p"^2 - 2) - (5"p" - 5/"p")`
= `(("p")^2 + (1/"p")^2 - 2 xx "p" xx 1/"p") - (5"p" - 5/"p")`
= `("p" - 1/"p")^2 - 5("p" - 1/"p")`
= `("p" - 1/"p")("p" - 1/"p" - 5)`.
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : ab - 2b + a2 - 2a
Factorise by the grouping method : (ax + by)2 + (bx - ay)2
Factorise by the grouping method : y2 - (a + b) y + ab
factorise: 8 + 6(a + b) - 5(a + b)2
factorise: a2 - 23a + 42
factorise: 1 - 18x - 63x2
factorise: (3x - 2y)2 - 5(3x - 2y) - 24
Factorise the following by grouping the terms:
15xy - 9x - 25y + 15
Factorise the following by grouping the terms:
x(x - 4)- x + 4
Factorise the following by grouping the terms:
x2 - (p + q)x + pq
