Advertisements
Advertisements
Question
Factorise the following by grouping the terms:
3ax2 - 5bx2 + 9az2 + 6ay2 - 10by2 - 15bz2
Sum
Advertisements
Solution
3ax2 - 5bx2 + 9az2 + 6ay2 - 10by2 - 15bz2
= 3ax2 + 6ay2 + 9az2 - 5bx2 - 10by2 - 15z2
= (3ax2 + 6ay2 + 9az2) - (5bx2 + 10by2 + 15bz2)
= 3a(x2 + 2y2 + 3z2) - 5b(x2 + 2y2 + 3z2)
= (x2 + 2y2 + 3z2)(3a - 5b).
shaalaa.com
Factorisation by Grouping
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise by the grouping method : a4 - 2a3 - 4a + 8
Factorise by the grouping method : a (a -4) - a + 4
Factorise : a3 -a2 +a -1
Factorise : 3x5 - 6x4 - 2x3 + 4x2 + x - 2
Factorise : - x2y - x + 3xy + 3
factorise: a2 - 5a+ 6
factorise: 4c2 + 3c - 10
factorise: 5 - 4x(1 + 3x)
Factorise the following by grouping the terms:
2m3 - 5n2 - 5m2n + 2mn
Factorise the following by grouping the terms:
2a + b + 3c - d + (2a + b)3 + (2a + b)2(3c - d)
