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Question
Factorise the following:
(a2 + 4b2 – c2)2 – 16a2b2
Sum
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Solution
Given: (a2 + 4b2 – c2)2 – 16a2b2
We know that,
(a + b)(a – b) = a2 – b2
Hence,
⇒ (a2 + 4b2 – c2) – (4ab)2
⇒ (a2 + 4b2 – c2 + 4ab)(a2 + 4b2 – c2 – 4ab)
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Chapter 4: Factorisation - EXERCISE 4B [Page 43]
