Advertisements
Advertisements
Question
Factorise the following:
64m3 – 343n3
Advertisements
Solution
We know that, x3 − y3 = (x − y)(x2 + xy + y2)
It is given that, 64m3 − 343n3 = (4m)3 − (7n)3
= (4m − 7n)[(4m)2 + (4m)(7n) + (7n)2]
= (4m − 7n)(16m2 + 28mn + 49n2)
APPEARS IN
RELATED QUESTIONS
Use suitable identity to find the following product:
`(y^2+3/2)(y^2-3/2)`
Expand the following, using suitable identity:
(–2x + 3y + 2z)2
Factorise the following:
27 – 125a3 – 135a + 225a2
Evaluate following using identities:
(a - 0.1) (a + 0.1)
If `x^2 + 1/x^2 = 66`, find the value of `x - 1/x`
Simplify the following products:
`(2x^4 - 4x^2 + 1)(2x^4 - 4x^2 - 1)`
Find the cube of the following binomials expression :
\[4 - \frac{1}{3x}\]
If x = −2 and y = 1, by using an identity find the value of the following
If \[\frac{a}{b} + \frac{b}{a} = - 1\] then a3 − b3 =
75 × 75 + 2 × 75 × 25 + 25 × 25 is equal to
If \[x^4 + \frac{1}{x^4} = 194,\] then \[x^3 + \frac{1}{x^3} =\]
If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]
If x + y = 1 and xy = -12; find:
x2 - y2.
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a" - (1)/"a"`
If p2 + q2 + r2 = 82 and pq + qr + pr = 18; find p + q + r.
If `"r" - (1)/"r" = 4`; find: `"r"^2 + (1)/"r"^2`
Simplify:
(x + 2y + 3z)(x2 + 4y2 + 9z2 - 2xy - 6yz - 3zx)
Simplify:
(2x - 4y + 7)(2x + 4y + 7)
Expand the following:
`(4 - 1/(3x))^3`
Find the value of x3 – 8y3 – 36xy – 216, when x = 2y + 6
