Find the Square of : 3a - 4b

Find the square of : 3a - 4b

Sum

We know that
( a - b )² = a² + b² - 2ab
( 3a - 4b )² = 9a² + 16b² - 2 x 3a x 4b
= 9a² + 16b² - 24ab

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Chapter 4: Expansions (Including Substitution) - Exercise 4 (A) [Page 57]

Chapter 4 Expansions (Including Substitution)
Exercise 4 (A) | Q 1.3 | Page 57

Write the following cube in expanded form:

(2a – 3b)³

Evaluate the following using identities:

(399)²

Prove that a² + b² + c² − ab − bc − ca is always non-negative for all values of a, b and c

Simplify: `(a + b + c)^2 - (a - b + c)^2`

Find the following product:

(3x − 4y + 5z) (9x² +16y²+ 25z² + 12xy −15zx + 20yz)

If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]

Use the direct method to evaluate :
(3x²+5y²) (3x²−5y²)

Evaluate: 20.8 × 19.2

If `"a" + 1/"a" = 6;`find `"a" - 1/"a"`

Simplify:
(x + y - z)² + (x - y + z)²