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Factorise the following: 64⁢x^3 − 27/y^3 - Mathematics

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Question

Factorise the following:

`64x^3 - 27/y^3`

Sum
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Solution

Given expression: `64x^3 - 27/y^3`

Step-wise calculation:

1. Rewrite each term as a cube:

`64x^3 = (4x)^3`

`27/y^3 = (3/y)^3`

2. The expression becomes a difference of cubes:

`(4x)^3 - (3/y)^3`

3. Use the difference of cubes factorization formula:

a3 – b3 = (a – b)(a2 + ab + b2) where a = 4x and `b = 3/y`.

4. Substitute into the formula:

`(4x - 3/y)((4x)^2 + (4x)(3/y) + (3/y)^2)`

5. Simplify inside the second bracket:

`(4x - 3/y)(16x^2 + (12x)/y + 9/y^2)`

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Chapter 4: Factorisation - Exercise 4E [Page 90]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 4 Factorisation
Exercise 4E | Q 8. | Page 90
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