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प्रश्न
Factorise the following:
`64x^3 - 27/y^3`
बेरीज
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उत्तर
Given expression: `64x^3 - 27/y^3`
Step-wise calculation:
1. Rewrite each term as a cube:
`64x^3 = (4x)^3`
`27/y^3 = (3/y)^3`
2. The expression becomes a difference of cubes:
`(4x)^3 - (3/y)^3`
3. Use the difference of cubes factorization formula:
a3 – b3 = (a – b)(a2 + ab + b2) where a = 4x and `b = 3/y`.
4. Substitute into the formula:
`(4x - 3/y)((4x)^2 + (4x)(3/y) + (3/y)^2)`
5. Simplify inside the second bracket:
`(4x - 3/y)(16x^2 + (12x)/y + 9/y^2)`
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