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Question
Factorise the following:
49(2x + y)2 – 64(x – 2y)2
Sum
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Solution
Given, 49(2x + y)2 – 64(x – 2y)2
⇒ [7(2x + y)]2 – [8(x – 2y)]2
We know that,
(a + b) (a – b) = a2 – b2
Hence,
⇒ [7(2x + y) + 8(x – 2y)] [7(2x + y) – 8(x – 2y)]
⇒ [14x + 7y + 8x – 16y] [14x + 7y – 8x + 16y]
⇒ [22x – 9y] [6x + 23y]
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