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Factorise the following: 36(a + 3)2 – 25(a – 2)2 - Mathematics

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Question

Factorise the following:

36(a + 3)2 – 25(a – 2)2

Sum
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Solution

To factorise 36(a + 3)2 – 25(a – 2)2 , we can treat it as a difference of squares.

First, notice that the expression is of the form A2 – B2, where:

A = 6(a + 3) and B = 5(a – 2)

Now, applying the difference of squares formula:

A2 – B2 = (A – B)(A + B)

Substitute A and B into the formula:

(6(a + 3) – 5(a – 2))(6(a + 3) + 5(a – 2)

Now simplify both terms:

1. For A – B:

6(a + 3) – 5(a – 2)

= 6a + 18 – 5a + 10

= a + 28

2. For A + B:

6(a + 3) + 5(a – 2)

= 6a + 18 + 5a – 10

= 11a + 8

Thus, the factorised form of 36(a + 3)2 – 25(a – 2)2 is (a + 28) (11a + 8)

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Chapter 4: Factorisation - EXERCISE 4B [Page 43]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 4 Factorisation
EXERCISE 4B | Q IV. 2. | Page 43
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