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प्रश्न
Factorise the following:
36(a + 3)2 – 25(a – 2)2
बेरीज
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उत्तर
To factorise 36(a + 3)2 – 25(a – 2)2 , we can treat it as a difference of squares.
First, notice that the expression is of the form A2 – B2, where:
A = 6(a + 3) and B = 5(a – 2)
Now, applying the difference of squares formula:
A2 – B2 = (A – B)(A + B)
Substitute A and B into the formula:
(6(a + 3) – 5(a – 2))(6(a + 3) + 5(a – 2)
Now simplify both terms:
1. For A – B:
6(a + 3) – 5(a – 2)
= 6a + 18 – 5a + 10
= a + 28
2. For A + B:
6(a + 3) + 5(a – 2)
= 6a + 18 + 5a – 10
= 11a + 8
Thus, the factorised form of 36(a + 3)2 – 25(a – 2)2 is (a + 28) (11a + 8)
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