Advertisements
Advertisements
Question
Factorise the following:
12x2 + 36x2y + 27y2x2
Advertisements
Solution
3x2[4 + 12y + 9y2]
= 3x2[9y2 + 12y + 4]
Product = 9 × 4 = 36, sum = 12
Split the middle term as 6y and 6y
12x2 + 36x2y + 21y2x2 = 3x2[9y2 + 12y + 4]
= 3x2[9y2 + 6y + 6y + 4]
= 3x2[3y(3y + 2) + 2(3y + 2)]
= 3x²(3y + 2)(3y + 2)
= 3x2(3y + 2)2
APPEARS IN
RELATED QUESTIONS
Write the coefficient of x2 in the following:
`pi/6x^2- 3x+4`
Show that (x − 2), (x + 3) and (x − 4) are factors of x3 − 3x2 − 10x + 24.
Using factor theorem, factorize each of the following polynomials:
x3 + 6x2 + 11x + 6
x3 + 2x2 − x − 2
x3 − 23x2 + 142x − 120
If \[x = \frac{1}{2}\] is a zero of the polynomial f(x) = 8x3 + ax2 − 4x + 2, find the value of a.
If x + 1 is a factor of x3 + a, then write the value of a.
When x3 − 2x2 + ax − b is divided by x2 − 2x − 3, the remainder is x − 6. The values of a and b are respectively
(x+1) is a factor of xn + 1 only if
If (3x − 1)7 = a7x7 + a6x6 + a5x5 +...+ a1x + a0, then a7 + a5 + ...+a1 + a0 =
