Advertisements
Advertisements
प्रश्न
Factorise the following:
12x2 + 36x2y + 27y2x2
Advertisements
उत्तर
3x2[4 + 12y + 9y2]
= 3x2[9y2 + 12y + 4]
Product = 9 × 4 = 36, sum = 12
Split the middle term as 6y and 6y
12x2 + 36x2y + 21y2x2 = 3x2[9y2 + 12y + 4]
= 3x2[9y2 + 6y + 6y + 4]
= 3x2[3y(3y + 2) + 2(3y + 2)]
= 3x²(3y + 2)(3y + 2)
= 3x2(3y + 2)2
APPEARS IN
संबंधित प्रश्न
Write the coefficient of x2 in the following:
`9-12x +X^3`
If `x = 2` is a root of the polynomial `f(x) = 2x2 – 3x + 7a` find the value of a.
f(x) = 3x4 + 17x3 + 9x2 − 7x − 10; g(x) = x + 5
f(x) = x3 −6x2 − 19x + 84, g(x) = x − 7
y3 − 2y2 − 29y − 42
x3 − 2x2 − x + 2
If x − 3 is a factor of x2 − ax − 15, then a =
If x + 2 and x − 1 are the factors of x3 + 10x2 + mx + n, then the values of m and n are respectively
Factorise the following:
9 – 18x + 8x2
(a + b – c)2 is equal to __________
