Advertisements
Advertisements
प्रश्न
Factorise the following:
12x2 + 36x2y + 27y2x2
Advertisements
उत्तर
3x2[4 + 12y + 9y2]
= 3x2[9y2 + 12y + 4]
Product = 9 × 4 = 36, sum = 12
Split the middle term as 6y and 6y
12x2 + 36x2y + 21y2x2 = 3x2[9y2 + 12y + 4]
= 3x2[9y2 + 6y + 6y + 4]
= 3x2[3y(3y + 2) + 2(3y + 2)]
= 3x²(3y + 2)(3y + 2)
= 3x2(3y + 2)2
APPEARS IN
संबंधित प्रश्न
f(x) = x3 −6x2 − 19x + 84, g(x) = x − 7
f(x) = x3 − 6x2 + 11x − 6, g(x) = x2 − 3x + 2
Find the values of a and b, if x2 − 4 is a factor of ax4 + 2x3 − 3x2 + bx − 4.
In the following two polynomials, find the value of a, if x − a is factor x6 − ax5 + x4 − ax3 + 3x − a + 2.
2y3 + y2 − 2y − 1
If x + 1 is a factor of x3 + a, then write the value of a.
Mark the correct alternative in each of the following:
If x − 2 is a factor of x2 + 3ax − 2a, then a =
If x + 2 is a factor of x2 + mx + 14, then m =
If x + 1 is a factor of the polynomial 2x2 + kx, then k =
(x + y)(x2 – xy + y2) is equal to
