Factorise by the Grouping Method: (2a-b)2 -10a + 5b

Factorise by the grouping method : (2a-b)² -10a + 5b

Sum

( 2a - b)² - 10a + 5b
= ( 2a - b )² - 5( 2a - b )
= ( 2a - b )( 2a - b - 5 )

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Factorisation by Grouping

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Chapter 5: Factorisation - Exercise 5 (A) [Page 69]

Chapter 5 Factorisation
Exercise 5 (A) | Q 13 | Page 69

Factorise by the grouping method : (ax + by)² + (bx - ay)²

Factorise by the grouping method : a (a -4) - a + 4

Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`

Factorise:

2a − 4b − xa + 2bx

Factorise : 6a² - 3a²b - bc² + 2c²

factorise: 3a² - 5a + 2

factorise: (2a + b)² + 5(2a + b) + 6

factorise: 8 + 6(a + b) - 5(a + b)²

Factorise the following by grouping the terms:

`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`

Factorise the following by grouping the terms:

`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`