Advertisements
Advertisements
Question
Factorise:
`(8"a"^3)/27 - "b"^3/8`
Sum
Advertisements
Solution
`(8"a"^3)/27 - "b"^3/8`
= `((2"a")/3)^3 - ("b"/2)^3`
= `( (2"a")/3 - "b"/2 )[((2"a")/3)^2 + (2"a")/3 xx "b"/2 + ("b"/2)^2 ]` ...[∵ a3 - b3 = (a - b)(a2 + ab + b2)]
= `((2"a")/3 - "b"/2)["4a"^2/9 + ("ab")/3 + "b"^2/4]`
shaalaa.com
Method of Factorisation : the Sum Or Difference of Two Cubes
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise : a6 + 27b3
Factorise : a3 + 0.064
Factorise : a3 + 0.064
Factorise : a3 + 0.064
Factorise : 1029 - 3x3
Show that : 353 + 273 is divisible by 62
Factorise : a6 - 7a3 - 8
Factorise:
a3 - 27b3 + 2a2b - 6ab2
Factorise :
8a3 − b3 − 4ax + 2bx
Evaluate :
`[ 5.67 xx 5.67 xx 5.67 + 4.33 xx 4.33 xx 4.33 ]/[5.67 xx 5.67 - 5.67 xx 4.33 + 4.33 xx 4.33]`
