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Question
Factorise:
a(3a - 2) - 1
Sum
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Solution
a(3a - 2) - 1
= 3a2 - 2a - 1
= 3a2 - 3a + a - 1
= 3a(a - 1) + 1(a - 1)
= (3a + 1)(a - 1)
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Is there an error in this question or solution?
Factorise:
a(3a - 2) - 1
a(3a - 2) - 1
= 3a2 - 2a - 1
= 3a2 - 3a + a - 1
= 3a(a - 1) + 1(a - 1)
= (3a + 1)(a - 1)