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Factorise: 24a3 + 37a2 - 5a - Mathematics

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Question

Factorise : 24a3 + 37a2 - 5a

Sum
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Solution

24a3 + 37a2 - 5a 
= a( 24a2 + 37a - 5 )
= a( 24a2 + 40a -3a - 5 )
= a x [ 8a( 3a + 5 ) - 1( 3a + 5 )]
= a[( 8a - 1 )( 3a + 5 )]
= a( 8a - 1 )( 3a + 5 )

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Chapter 5: Factorisation - Exercise 5 (B) [Page 71]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 5 Factorisation
Exercise 5 (B) | Q 6 | Page 71
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