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Factorise: 64a6 – 729b6 - Mathematics

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Question

Factorise:

64a6 – 729b6

Sum
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Solution

To factorise: 64a6 – 729b6

Factorise the given expression by using identity.

64a2 = (2a2)3,

729b6 = (3b2)3

So, 64a2 – 729b6 = (2a2)3 – (3b2)3

Let a = 2a2

b = 3b2

= (2a2 – 3b2) (4a4 + 6a2b2 + 9b4)

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Chapter 4: Factorisation - EXERCISE 4D [Page 46]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 4 Factorisation
EXERCISE 4D | Q I. 14. | Page 46
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