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Question
Factorise:
15625a6 – 64b6
Sum
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Solution
Factorise 15625a6 – 64b6 stepwise, formal
Step 1: Write as perfect sixth powers
15625a6 – 64b6 = 56a6 – 26b6
= [(5a)3]2 – [(2b)3]2
= (125a3)2 – (8b3)2
Step 2: Use difference of squares X2 – Y2 = (X – Y) (X + Y)
(125a3)2 – (8b3)2 = (125a3 – 8b3) (125a3 + 8b3)
Step 3: Factor each cubic (cube identities)
A3 – B3 = (A – B) (A2 + AB + B2),
A3 + B3 = (A + B) (A2 – AB + B2)
With A = 5a, B = 2b:
125a3 – 8b3 = (5a – 2b) (25a2 + 10ab + 4b2),
125a3 + 8b3 = (5a + 2b) (25a2 – 10ab + 4b2).
Step 4: Combine the factors
(5a – 2b) (25a2 + 10ab + 4b2) (5a + 2b) (25a2 – 10ab + 4b2)
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