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Question
Factorise:
3a7 – 192ab6
Sum
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Solution
Given expression: 3a7 – 192ab6
⇒ 3a(a2)3 – (4b2)3]
⇒ 3a[(a2)3 – (4b2)3]
We know that,
a3 – b3 = (a – b) (a2 + ab + b2)
Hence,
⇒ 3a(a2 – 4b2) (a4 + 4a2b2 + 16b4)
⇒ 3a[(a)2 – (2b)2 ] (a4 + 4a2b2 + 16b4)
⇒ 3a(a – 2b) (a + 2b) (a4 + 4a2b2 + 16b4)
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