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Question
Express the following as the difference of two squares:
(x2 + 5x + 6) (x2 – 5x – 6)
Sum
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Solution
Given: (x2 + 5x + 6) (x2 – 5x – 6)
Step-wise calculation:
1. First, notice that both factors can be seen as conjugates but rearranged:
(x2 + 5x + 6) and (x2 – 5x – 6)
2. Observe that if you treat the second factor’s terms related to the first factor’s, you get a structure like:
(x2) + (5x + 6) and (x2) – (5x + 6)
3. Then the original product can be rewritten as:
(x2 + 5x + 6)(x2 – 5x – 6)
= (x2 + (5x + 6))(x2 – (5x + 6))
4. Recognize this as the difference of two squares formula:
(a + b)(a – b) = a2 – b2
where a = x2 and b = 5x + 6.
5. Therefore, (x2 + 5x + 6)(x2 – 5x – 6) = (x2)2 – (5x + 6)2.
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Chapter 4: Factorisation - Exercise 4C [Page 82]
