Express in Terms of Log 2 and Log 3 : Log 36 - Mathematics

Express in terms of log 2 and log 3 : log 36

Sum

log 36 = log( 2 x 2 x 3 x 3 )
= log( 2² x 3² )
= log( 2² ) + log( 3² ) ....[ log_amn = log_am + log_an ]
= 2log2 + 2log3 .....[ log_amⁿ = nlog_am ]

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Laws of Logarithm

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Chapter 8: Logarithms - Exercise 8 (B) [Page 106]

Chapter 8 Logarithms
Exercise 8 (B) | Q 1.1 | Page 106

Express in terms of log 2 and log 3:

`log26/51 - log91/119`

Express the following in a form free from logarithm:

2 log x - log y = 1

Prove that : `2"log" 15/18 - "log"25/162 + "log"4/9 = log 2 `

Find x, if : x - log 48 + 3 log 2 = `1/3`log 125 - log 3.

Express log₁₀2 + 1 in the form of log₁₀x .

Solve for x : log (x - 2) + log (x + 2) = log 5

Solve for x : ` ( log 128) / ( log 32 ) ` = x

If log₁₀2 = a and log₁₀3 = b; express each of the following in terms of 'a' and 'b' : log `3 1/8`

State, true or false :
`log x/log y` = log x - log y

If log₁₀ 8 = 0.90, find the value of:

log₁₀ 4