Express in Terms of Log 2 and Log 3 : Log 36

Express in terms of log 2 and log 3 : log 36

बेरीज

log 36 = log( 2 x 2 x 3 x 3 )
= log( 2² x 3² )
= log( 2² ) + log( 3² ) ....[ log_amn = log_am + log_an ]
= 2log2 + 2log3 .....[ log_amⁿ = nlog_am ]

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Laws of Logarithm

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पाठ 8: Logarithms - Exercise 8 (B) [पृष्ठ १०६]

पाठ 8 Logarithms
Exercise 8 (B) | Q 1.1 | पृष्ठ १०६

Express in terms of log 2 and log 3:

log 144

Express in terms of log 2 and log 3 :
`"log"75/16 - 2"log"5/9 + "log"32/243`

Express the following in a form free from logarithm:
2 log x + 3 log y = log a

Express log₁₀2 + 1 in the form of log₁₀x .

Solve for x : `(log 81)/(log27 )` = x

Solve for x : ` (log 64)/(log 8)` = log x

If log₁₀2 = a and log₁₀3 = b; express each of the following in terms of 'a' and 'b' : log 60

If log₁₀2 = a and log₁₀3 = b; express each of the following in terms of 'a' and 'b' : log `3 1/8`

State, true or false :
If `log 25/log 5 = log x`, then x = 2.

State, true or false :
log x x log y = log x + log y