Advertisements
Advertisements
प्रश्न
Express in terms of log 2 and log 3 : log 36
Advertisements
उत्तर
log 36 = log( 2 x 2 x 3 x 3 )
= log( 22 x 32 )
= log( 22 ) + log( 32 ) ....[ logamn = logam + logan ]
= 2log2 + 2log3 .....[ logamn = nlogam ]
APPEARS IN
संबंधित प्रश्न
Express in terms of log 2 and log 3:
log 144
Express in terms of log 2 and log 3 : log 4.5
Express in terms of log 2 and log 3:
`log26/51 - log91/119`
Express log102 + 1 in the form of log10x .
Solve for x : log (x2 - 21) = 2.
Solve for x : ` ( log 128) / ( log 32 ) ` = x
If log102 = a and log103 = b; express each of the following in terms of 'a' and 'b' : log `3 1/8`
State, true or false :
`log x/log y` = log x - log y
State, true or false :
log x x log y = log x + log y
Given that log x = m + n and log y = m - n, express the value of log ` ( 10x ) / ( y ^ 2 )` in terms of m and n.
