Solve for X : Log (X2 - 21) = 2

Solve for x : log (x² - 21) = 2.

बेरीज

log ( x² - 21 ) = 2
⇒ log ( x² - 21) = log 100
⇒ x² - 21 - 100 = 0
⇒ x² - 121 = 0
⇒ x² = 121
⇒ x = `+- sqrt121`
⇒ x =`+-`11

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Laws of Logarithm

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पाठ 8: Logarithms - Exercise 8 (B) [पृष्ठ १०६]

पाठ 8 Logarithms
Exercise 8 (B) | Q 7.2 | पृष्ठ १०६

Express in terms of log 2 and log 3 : log 4.5

Express in terms of log 2 and log 3:

`log26/51 - log91/119`

Express in terms of log 2 and log 3 :
`"log"75/16 - 2"log"5/9 + "log"32/243`

Express log₁₀2 + 1 in the form of log₁₀x .

Solve for x : `(log 81)/(log27 )` = x

If log 2 = 0.3010 and log 3 = 0.4771; find the value of : log 25

If log₁₀2 = a and log₁₀3 = b ; express each of the following in terms of 'a' and 'b': log 12

State, true or false :
If `log 25/log 5 = log x`, then x = 2.

Given that log x = m + n and log y = m - n, express the value of log ` ( 10x ) / ( y ^ 2 )` in terms of m and n.

If log₁₀ 8 = 0.90, find the value of:

log₁₀ 4