Express Log102 + 1 in the Form of Log10x.

Express log₁₀2 + 1 in the form of log₁₀x .

बेरीज

log₁₀2 + 1

= log₁₀2 + log₁₀10 ....[ ∵ log₁₀10 = 1 ]

= log₁₀2 x 10 ....[ log_am + log_an = log_amn ]

= log₁₀20.

shaalaa.com

Laws of Logarithm

या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

पाठ 8: Logarithms - Exercise 8 (B) [पृष्ठ १०६]

पाठ 8 Logarithms
Exercise 8 (B) | Q 6 | पृष्ठ १०६

Express in terms of log 2 and log 3 :
`"log"75/16 - 2"log"5/9 + "log"32/243`

Express the following in a form free from logarithm:
a log x - b log y = 2 log 3

Evaluate the following without using tables :
log 5 + log 8 - 2 log 2

Prove that : `2"log" 15/18 - "log"25/162 + "log"4/9 = log 2 `

If log₁₀2 = a and log₁₀3 = b ; express each of the following in terms of 'a' and 'b': log `2 1/4`

If log₁₀2 = a and log₁₀3 = b ; express each of the following in terms of 'a' and 'b' : log 5.4

Solve for x : ` (log 64)/(log 8)` = log x

If log₁₀2 = a and log₁₀3 = b; express each of the following in terms of 'a' and 'b' : log 60

State, true or false :
If `log 25/log 5 = log x`, then x = 2.

State, true or false :
log x x log y = log x + log y