Express Log102 + 1 in the Form of Log10x.

Express log₁₀2 + 1 in the form of log₁₀x .

बेरीज

log₁₀2 + 1

= log₁₀2 + log₁₀10 ....[ ∵ log₁₀10 = 1 ]

= log₁₀2 x 10 ....[ log_am + log_an = log_amn ]

= log₁₀20.

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Laws of Logarithm

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पाठ 8: Logarithms - Exercise 8 (B) [पृष्ठ १०६]

पाठ 8 Logarithms
Exercise 8 (B) | Q 6 | पृष्ठ १०६

Express in terms of log 2 and log 3 :
`"log"75/16 - 2"log"5/9 + "log"32/243`

Find x, if : x - log 48 + 3 log 2 = `1/3`log 125 - log 3.

If log 2 = 0.3010 and log 3 = 0.4771; find the value of : log 25

If log 2 = 0.3010 and log 3 = 0.4771; find the value of:

`2/3` log 8

If log₁₀2 = a and log₁₀3 = b ; express each of the following in terms of 'a' and 'b': log `2 1/4`

Solve for x :
`log 225/log15` = log x

If log₁₀2 = a and log₁₀3 = b; express each of the following in terms of 'a' and 'b' : log 60

State, true or false :
If `log 25/log 5 = log x`, then x = 2.

Given that log x = m + n and log y = m - n, express the value of log ` ( 10x ) / ( y ^ 2 )` in terms of m and n.

If log₁₀ 8 = 0.90, find the value of:

log₁₀ 4