Express Log102 + 1 in the Form of Log10x. - Mathematics

Express log₁₀2 + 1 in the form of log₁₀x .

योग

log₁₀2 + 1

= log₁₀2 + log₁₀10 ....[ ∵ log₁₀10 = 1 ]

= log₁₀2 x 10 ....[ log_am + log_an = log_amn ]

= log₁₀20.

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Laws of Logarithm

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अध्याय 8: Logarithms - Exercise 8 (B) [पृष्ठ १०६]

अध्याय 8 Logarithms
Exercise 8 (B) | Q 6 | पृष्ठ १०६

Express in terms of log 2 and log 3:

`log26/51 - log91/119`

Express the following in a form free from logarithm:
2 log x + 3 log y = log a

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Solve for x : log₁₀ (x - 10) = 1

Solve for x : log (x² - 21) = 2.

Solve for x : log (x + 5) + log (x - 5) = 4 log 2 + 2 log 3

If log 2 = 0.3010 and log 3 = 0.4771; find the value of : log 3.6

If log 2 = 0.3010 and log 3 = 0.4771; find the value of:

`2/3` log 8

If log₁₀2 = a and log₁₀3 = b ; express each of the following in terms of 'a' and 'b': log `2 1/4`

State, true or false : log 1 x log 1000 = 0