Advertisements
Advertisements
प्रश्न
Solve for x :
`log 225/log15` = log x
Advertisements
उत्तर
⇒ log x = ` (log 225 ) / (log15 )`
⇒ log x = ` ( log 15 xx 15 ) / ( log 15 ) `
⇒ log x = ` ( log 15 ^ 2 ) / ( log 15 ) `
⇒ log x = ` ( 2 log 15 ) / ( log 15 ) ` .... [ n loga m = loga mn ]
⇒ log x = 2
⇒ log10 x = 2
⇒102 = x
⇒ x = 10 x 10
⇒ x = 100.
APPEARS IN
संबंधित प्रश्न
Express in terms of log 2 and log 3 :
`"log"75/16 - 2"log"5/9 + "log"32/243`
Express the following in a form free from logarithm:
2 log x - log y = 1
Express the following in a form free from logarithm:
a log x - b log y = 2 log 3
Solve for x : log (x + 5) + log (x - 5) = 4 log 2 + 2 log 3
If log 2 = 0.3010 and log 3 = 0.4771; find the value of : log 3.6
If log102 = a and log103 = b ; express each of the following in terms of 'a' and 'b': log 12
If log102 = a and log103 = b; express each of the following in terms of 'a' and 'b' : log 60
If log102 = a and log103 = b; express each of the following in terms of 'a' and 'b' : log `3 1/8`
State, true or false :
If `log 25/log 5 = log x`, then x = 2.
State, true or false :
log x x log y = log x + log y
