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प्रश्न
Express in terms of log 2 and log 3:
`log26/51 - log91/119`
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उत्तर
`log26/51 - log91/119`
= `log((26/51)/(91/119)) ...[ log_am - log_an = log_a(m/n)]`
= `log26/51 xx 119/91`
= `log [ 2 xx 13 ]/[ 3 xx 17 ] xx [ 7 xx 17 ] /[ 7 xx 13 ]`
= `log 2/3`
= log 2 − log 3 ...[loga`m/n` = logam − logan]
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