Question

Solve for x : ` ( log 128) / ( log 32 ) ` = x

Answer 1

 ` ( log 128 ) / ( log 32 ) ` = x

`=> x =( log 128 )/ ( log 32 )`

`=> x= (log 2xx 2xx 2xx 2xx 2xx 2xx 2)/ (log 2xx 2xx 2xx 2xx 2 ) `

`=> x = log 2^7 / log2^5`

`=> x = ( 7 log 2 )/ ( 5 log 2 ) `     ... [ n log_a m = log_a mⁿ  ]

` => x = ( 7 ) / ( 5 )`

⇒ x = 1.4