Advertisements
Advertisements
प्रश्न
Evaluate the following without using tables :
log 4 + `1/3` log 125 - `1/5`log 32
Advertisements
उत्तर
Consider the given expression
log 4 + `1/3"log 125" - 1/5` log 32
= `log 4 + log ( 125 )^(1/3) - log(32)^(1/5)` ...[ nlogam = logamn ]
= `log 4 + log(5^3)^(1/3) - log(2^5)^(1/5)`
= log 4 + log 5 - log 2
= log 4 x 5 - log 2 ....[ logam + logan = logamn]
= `"log"(20/2) .....[ log_am - log_an = log_a(m/n)]`
= log 10
= 1
APPEARS IN
संबंधित प्रश्न
Express in terms of log 2 and log 3:
`log26/51 - log91/119`
Express in terms of log 2 and log 3 :
`"log"75/16 - 2"log"5/9 + "log"32/243`
Evaluate the following without using tables :
log 5 + log 8 - 2 log 2
Express log102 + 1 in the form of log10x .
Solve for x : log10 (x - 10) = 1
Solve for x : log (x + 5) + log (x - 5) = 4 log 2 + 2 log 3
If log 2 = 0.3010 and log 3 = 0.4771; find the value of : log 3.6
Solve for x : ` ( log 128) / ( log 32 ) ` = x
If log102 = a and log103 = b ; express each of the following in terms of 'a' and 'b': log 12
Given that log x = m + n and log y = m - n, express the value of log ` ( 10x ) / ( y ^ 2 )` in terms of m and n.
