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Question
Explain the following reaction with the balanced equation.
Aluminium reacts with dil hydrochloric acid
Short/Brief Note
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Solution
When aluminium is treated with dilute hydrochloric acid, it forms aluminium chloride with release of hydrogen gas.
\[\ce{\underset{\text{Aluminium}}{2Al_{(s)}} + \underset{\text{Hydrochloric acid}}{6HCl_{(aq)}} -> \underset{\text{Aluminium chloride}}{2AlCl_{3(aq)}} + \underset{\text{Hydrogen}}{3H2↑}}\]
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