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Question
Explain the following reaction with the balanced equation.
Reaction of zinc with dil hydrochloric acid
Short/Brief Note
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Solution
Zinc, on treatment with dilute hydrochloric acid, forms zinc chloride with release of hydrogen gas.
\[\ce{\underset{\text{Zinc}}{Zn_{(s)}} + \underset{\text{Hydrochloric acid}}{2HCl_{(aq)}} -> \underset{\text{Zinc chloride}}{ZnCl_{2(aq)}} + \underset{\text{Hydrogen}}{H2↑}}\]
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