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Question
Explain how a square is a rhombus.
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Solution
A square is a rhombus since its four sides are of the same length.
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In a quadrilateral ABCD, AB = AD and CB = CD.
Prove that:
- AC bisects angle BAD.
- AC is the perpendicular bisector of BD.
ABCD is a square. A is joined to a point P on BC and D is joined to a point Q on AB. If AP = DQ;
prove that AP and DQ are perpendicular to each other.
Prove that the quadrilateral formed by joining the mid-points of a square is also a square.
In the given figure, ΔPQR is right-angled at P. PABQ and QRST are squares on the side PQ and hypotenuse QR. If PN ⊥ TS, show that:
(a) ΔQRB ≅ ΔPQT
(b) Area of square PABQ = area of rectangle QTNM.
In the given figure AF = BF and DCBF is a parallelogram. If the area of ΔABC is 30 square units, find the area of the parallelogram DCBF.
In a parallelogram PQRS, M and N are the midpoints of the sides PQ and PS respectively. If area of ΔPMN is 20 square units, find the area of the parallelogram PQRS.
