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Question
In a parallelogram PQRS, M and N are the midpoints of the sides PQ and PS respectively. If area of ΔPMN is 20 square units, find the area of the parallelogram PQRS.
Sum
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Solution
Construction: Join SM and SQ.
In a parallelogram PQRS, SQ is the diagonal.
So, it bisects the parallelogram.
∴ Area(DPSQ) = `(1)/(2) xx "Area(parallelogram PQRS)"`
SM is the median of ΔPSQ.
∴ Area(ΔPSM) = `(1)/(2) xx "Area(ΔPSQ)"`
= `(1)/(2) xx (1)/(2) xx "Area(parallelogram PQRS)"`
= `(1)/(4) xx "Area(parallelogram PQRS)"`
Again, MN is the median of ΔPSM.
∴ Area(ΔPMN) = `(1)/(2) xx "Area(ΔPSM)"`
= `(1)/(2) xx (1)/(4) xx "Area(parallelogram PQRS)"`
= `(1)/(8) xx "Area(parallelogram PQRS)"`
⇒ 20 = `(1)/(8) xx "Area(parallelogram PQRS)"`
⇒ Area(parallelogram PQRS) = 160 square units.
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