English

Evaluate the following limit : limx→0[3+x3-x]1x - Mathematics and Statistics

Advertisements
Advertisements

Question

Evaluate the following limit : 

`lim_(x -> 0) [(3 + x)/(3 - x)]^(1/x)`

Sum
Advertisements

Solution

`lim_(x -> 0) [(3 + x)/(3 - x)]^(1/x)`

= `lim_(x -> 0) [(1 + x/3)/(1 - x/3)]^(1/x)   ...[("Divide numerator and"),("denominator by 3")]`

= `lim_(x -> 0) (1 + x/3)^(1/x)/(1 - x/3)^(1/x)`

= `lim_(x -> 0) ((1 + x/3)^(3/x xx 1/3))/((1 - x/3)^((-3)/x xx 1/3))`

= `(lim_(x -> 0)[(1 + x/3)^(3/x)]^(1/3))/(lim_(x -> 0) [(1 - x/3)^((-3)/x)]^(-1/3)`

= `"e"^(1/3)/"e"^((-1)/3)  ...[(because x -> 0","  x/3 -> 0"," (-x)/3 -> 0 and),(lim_(x -> 0) (1 + x)^(1/x) = "e")]`

= `"e"^(1/3 + 1/3)`

= `"e"^(2/3)`

shaalaa.com
Limits of Exponential and Logarithmic Functions
  Is there an error in this question or solution?
Chapter 7: Limits - Exercise 7.6 [Page 154]

RELATED QUESTIONS

Evaluate the following: `lim_(x -> 0)[(log(2 + x) - log( 2 - x))/x]`


Evaluate the following: `lim_(x -> 0) [("a"^(3x) - "b"^(2x))/(log 1 + 4x)]`


Evaluate the following: `lim_(x -> 0) [(2^x - 1)^2/((3^x - 1) xx log (1 + x))]`


Evaluate the following: `lim_(x -> 0)[(15^x - 5^x - 3^x +1)/x^2]`


Evaluate the following Limits: `lim_(x -> 0)[(5^x - 1)/x]`


Evaluate the following Limits: `lim_(x -> 0) ("e"^x + e^(-x) - 2)/x^2`


Evaluate the following Limits: `lim_(x -> 0)[(x(6^x - 3^x))/((2^x - 1)*log(1 + x))]`


Evaluate the following Limits: `lim_(x -> 0)[((5^x - 1)^2)/(x*log(1 + x))]`


Evaluate the following limit : 

`lim_(x -> 0) [(9^x - 5^x)/(4^x - 1)]`


Evaluate the following limit : 

`lim_(x -> 0) [(6^x + 5^x + 4^x - 3^(x + 1))/sinx]`


Evaluate the following limit : 

`lim_(x -> 0) [(log(3 - x) - log(3 + x))/x]`


Select the correct answer from the given alternatives.

`lim_(x -> 0) ((3 + 5x)/(3 - 4x))^(1/x)` =


Select the correct answer from the given alternatives.

`lim_(x -> pi/2) ((3^(cosx) - 1)/(pi/2 - x))` =


Select the correct answer from the given alternatives.

`lim_(x→0)[(3^(sinx) - 1)^3/((3^x - 1).tan x.log(1 + x))]` =


Select the correct answer from the given alternatives.

`lim_(x -> 3) [(5^(x - 3) - 4^(x - 3))/(sin(x - 3))]` =


Evaluate the following :

`lim_(x -> 0)[("e"^x + "e"^-x - 2)/(x*tanx)]`


lf the function f(x) satisfies `lim_{x→1}(2f(x) - 5)/(2(x^2 - 1)) = e`, then `lim_{x→1}f(x)` is ______ 


`lim_(x -> 0) (sin^4 3x)/x^4` = ________.


`lim_(x -> 0) (15^x - 3^x - 5^x + 1)/(xtanx)` is equal to ______.


Evaluate the following:

`lim_(x->0)[((25)^x -2(5)^x+1)/x^2]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/x^2]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/x^2]`


Evaluate the following :

`lim_(x->0)[((25)^x -2 (5)^x +1)/(x^2)]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/(x^2)]`


Evaluate the following:

`lim_(x->0)[((25)^x -2(5)^x + 1)/x^2]`


Evaluate the following:

`lim_(x -> 0)[((25)^x - 2(5)^x + 1)/x^2]`


Evaluate the following:

`lim_(x->0)[((25)^x-2(5)^x+1)/x^2]`


Evaluate the limit: 

`lim_(z->2)[(z^2-5x+6)/(z^2-4)]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/x^2]`


Evaluate the following:

`lim_(x->0)[((25)^x -2(5)^x +1)/(x^2)]`


Evaluate the following:

`lim_(x->0) [((25)^x - 2(5)^x + 1)/x^2]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×