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Evaluate the following limit : limx→0[3+x3-x]1x - Mathematics and Statistics

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प्रश्न

Evaluate the following limit : 

`lim_(x -> 0) [(3 + x)/(3 - x)]^(1/x)`

योग
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उत्तर

`lim_(x -> 0) [(3 + x)/(3 - x)]^(1/x)`

= `lim_(x -> 0) [(1 + x/3)/(1 - x/3)]^(1/x)   ...[("Divide numerator and"),("denominator by 3")]`

= `lim_(x -> 0) (1 + x/3)^(1/x)/(1 - x/3)^(1/x)`

= `lim_(x -> 0) ((1 + x/3)^(3/x xx 1/3))/((1 - x/3)^((-3)/x xx 1/3))`

= `(lim_(x -> 0)[(1 + x/3)^(3/x)]^(1/3))/(lim_(x -> 0) [(1 - x/3)^((-3)/x)]^(-1/3)`

= `"e"^(1/3)/"e"^((-1)/3)  ...[(because x -> 0","  x/3 -> 0"," (-x)/3 -> 0 and),(lim_(x -> 0) (1 + x)^(1/x) = "e")]`

= `"e"^(1/3 + 1/3)`

= `"e"^(2/3)`

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अध्याय 7: Limits - Exercise 7.6 [पृष्ठ १५४]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Limits
Exercise 7.6 | Q II. (2) | पृष्ठ १५४

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\[\lim_{x\to0}\frac{\mathrm{e}^{\tan x}-\mathrm{e}^{x}}{\tan x-x}=\]


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