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Select the correct answer from the given alternatives. limx→0(15x-3x-5x+1sin2x) =

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प्रश्न

Select the correct answer from the given alternatives.

`lim_(x -> 0) ((15^x - 3^x - 5^x + 1)/sin^2x)` =

विकल्प

  • log 15

  • log 3 + log 5

  • log 3 . log 5

  • 3 log 5

MCQ
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उत्तर

log 3 . log 5

Explanation;

`lim_(x -> 0) ((15^x - 3^x - 5^x + 1)/sin^2x)` 

= `lim_(x -> 0)[((5^x - 1)(3^x - 1))/x^2 xx x^2/sin^2x]  ...[(because x -> 0","  x ≠ 0),(therefore x^2 ≠ 0)]`

= log 3 . log 5

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Limits - Miscellaneous Exercise 7.1 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Limits
Miscellaneous Exercise 7.1 | Q I. (8) | पृष्ठ १५८

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