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Evaluate the following Limits: limx→0[log100+log(0.01+x)x]

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प्रश्न

Evaluate the following Limits: `lim_(x -> 0)[(log 100 + log (0.01 + x))/x]`

योग
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उत्तर

`lim_(x -> 0)[(log 100 + log (0.01 + x))/x]`

= `lim_(x -> 0) log[100 (0.01 + x)]/x`

= `lim_(x -> 0) (log(1 + 100x))/x`

= `lim_(x -> 0)[(log(1 + 100x))/(100x)] xx 100`

= 1 x 100    ...`[("As"  x -> 0","  100  x -> 0 and ),(lim_(x -> 0) (log(1 + x))/x = 1)]` 

= 100

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अध्याय 7: Limits - MISCELLANEOUS EXERCISE - 7 [पृष्ठ १०६]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 11 Maharashtra State Board
अध्याय 7 Limits
MISCELLANEOUS EXERCISE - 7 | Q II. 17) | पृष्ठ १०६

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