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Evaluate the following limit : limx→0[(49)x-2(35)x+(25)xsinx⋅log(1+2x)]

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प्रश्न

Evaluate the following limit :

`lim_(x -> 0) [((49)^x - 2(35)^x + (25)^x)/(sinx* log(1 + 2x))]`

योग
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उत्तर

`lim_(x -> 0) [((49)^x - 2(35)^x + (25)^x)/(sinx* log(1 + 2x))]`

= `lim_(x -> 0) ((7^x)^2 - 2(7^x) (5^x) + (5^x)^2)/(sinx log (1 + 2x))  ...[(35^x = (5*7)^x = 5^x * 7^x),(49^x = (7^2)x = (7^x)^2)]`

= `lim_(x -> 0) [7^x - 5^x]^2/(sinx log (1 + 2x)`

= `lim_(x -> 0) [(7^x - 1) - (5^x- 1)]^2/(sin x log (1 + 2x))`

= `lim_(x -> 0) [(7^x - 1)/x - (5^x - 1)/x]^2/([sinx/x][(log(1 + 2x))/x])`   ...[∵ x → 0, ∴ x ≠ 0]

= `([lim_(x -> 0) ((7^x - 1)/x - (5^x - 1)/x)]^2)/([lim_(x -> 0) sinx/x] xx 2 [lim_(x -> 0)  (log(1 + 2x))/(2x)]`

= `[log 7  - log 5]^2/([1] xx 2[1])    ...[because x -> 0 ","  2x -> 0  "and" lim_(x -> 0) (log(1 + x))/x = 1  "and" lim_(x -> 0) ("a"^x - 1)/x = log"a"]`

= `1/2[log(7/5)]^2`

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अध्याय 7: Limits - Exercise 7.6 [पृष्ठ १५४]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Limits
Exercise 7.6 | Q III. (5) | पृष्ठ १५४

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