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Evaluate the following limit : limx→0[(2x-1)3(3x-1)⋅sinx⋅log(1+x)]

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प्रश्न

Evaluate the following limit : 

`lim_(x -> 0)[(2^x - 1)^3/((3^x - 1)*sinx*log(1 + x))]`

योग
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उत्तर

`lim_(x -> 0)(2^x - 1)^3/((3^x - 1)*sinx*log(1 + x))`

= `lim_(x -> 0)((2^x - 1)^3/x^3)/(((3^x - 1)*sinx*log(1 + x))/x^3)   ...[("Divide numerator and"),("denominator by"  x^3.),(because x -> 0","  x ≠ 0),(therefore x^3 ≠ 0)]`

= `(lim_(x -> 0) ((2^x - 1)/x)^3)/(lim_(x -> 0) ((3^x - 1)/x)* sinx/x* (log(1 + x))/x`

= `(lim_(x -> 0) (2^x - 1)/x)^3/((lim_(x -> 0) (3^x - 1)/x)*(lim_(x -> 0)sinx/x)(lim_(x -> 0) (log(1 + x))/x)`

= `(log2)^3/((log3)(1)(1))  ....[lim_(x -> 0) ("a"^x - 1)/x = log"a"]`

= `(log2)^3/log3`

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अध्याय 7: Limits - Exercise 7.6 [पृष्ठ १५४]

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