English

Evaluate the following: d∫xx4-1dx - Mathematics

Advertisements
Advertisements

Question

Evaluate the following:

`int x/(x^4 - 1) "d"x`

Sum
Advertisements

Solution

Let I = `int x/(x^4 - 1) "d"x`

Put x2 = t

⇒ 2x dx = dt

⇒ x dx = `"dt"/2`

`1/2 int "dt"/("t"^2 - 1) = 1/2 int "dt"/("t"^2 - (1)^2)`

= `1/2 * 1/(2 * 1) log |("t" - 1)/("t" + 1)| + "C"`  ....`[because int 1/(x^2 - "a"^2) "d"x = 1/(2"a") log |(x - "a")/(x + "a")| + "C"]`

= `1/4 log |(x^2 - 1)/(x^2 + 1)| + "C"`

Hence, I = `1/4 log |(x^2 - 1)/(x^2 + 1)| + "C"`

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Integrals - Exercise [Page 164]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 12
Chapter 7 Integrals
Exercise | Q 18 | Page 164

RELATED QUESTIONS

`∫   x    \sqrt{x + 2}     dx ` 

\[\int\frac{x}{\sqrt{x + 4}} dx\]

\[\int\frac{1 + \tan x}{1 - \tan x} dx\]

\[\int\frac{1}{x \log x} dx\]

\[\int\frac{{cosec}^2 x}{1 + \cot x} dx\]

\[\int\frac{1}{\sqrt{x}\left( \sqrt{x} + 1 \right)} dx\]

\[\int\frac{1}{\sin x \cos^2 x} dx\]

 ` ∫       cot^3   x  "cosec"^2   x   dx `


 `   ∫     tan x    .  sec^2 x   \sqrt{1 - tan^2 x}     dx\ `

Evaluate the following integrals:

\[\int\frac{1}{\left( x^2 + 2x + 10 \right)^2}dx\]

 


Evaluate the following integrals:

\[\int\frac{5x - 2}{1 + 2x + 3 x^2} \text{ dx }\]

\[\int\frac{1}{5 - 4 \cos x} \text{ dx }\]

Evaluate the following integrals:

\[\int\frac{\log x}{\left( x + 1 \right)^2}dx\]

 


Evaluate the following integrals:

\[\int\left( x + 3 \right)\sqrt{3 - 4x - x^2} \text{  dx }\]

\[\int(3x + 1) \sqrt{4 - 3x - 2 x^2} \text{  dx }\]

\[\int\frac{a x^2 + bx + c}{\left( x - a \right) \left( x - b \right) \left( x - c \right)} dx,\text{ where a, b, c are distinct}\]

Evaluate the following integral:

\[\int\frac{x^3 + x + 1}{x^2 - 1}dx\]

Evaluate the following integral:

\[\int\frac{3x - 2}{\left( x + 1 \right)^2 \left( x + 3 \right)}dx\]

\[\int\frac{2x + 1}{\left( x + 2 \right) \left( x - 3 \right)^2} dx\]

Evaluate the following integral:

\[\int\frac{x^2}{x^4 - x^2 - 12}dx\]

 


\[\int\frac{( x^2 + 1) ( x^2 + 4)}{( x^2 + 3) ( x^2 - 5)} dx\]

Write a value of

\[\int\frac{\left( \log x \right)^n}{x} \text{ dx }\]

Evaluate:\[\int\frac{x^2}{1 + x^3} \text{ dx }\] .


Evaluate:\[\int\frac{\sin \sqrt{x}}{\sqrt{x}} \text{ dx }\]


Evaluate:\[\int\frac{\cos \sqrt{x}}{\sqrt{x}} \text{ dx }\]


Evaluate:\[\int\frac{\left( 1 + \log x \right)^2}{x} \text{   dx }\]


Evaluate:\[\int\frac{\log x}{x} \text{ dx }\]


Evaluate: \[\int\frac{x^3 - x^2 + x - 1}{x - 1} \text{ dx }\]


Evaluate:\[\int\frac{e\tan^{- 1} x}{1 + x^2} \text{ dx }\]


Evaluate: \[\int\frac{1}{\sqrt{1 - x^2}} \text{ dx }\]


Write the value of\[\int\sec x \left( \sec x + \tan x \right)\text{  dx }\]


Evaluate: \[\int\left( 1 - x \right)\sqrt{x}\text{  dx }\]


Evaluate:

\[\int \cos^{-1} \left(\sin x \right) \text{dx}\]


Evaluate: `int_  (x + sin x)/(1 + cos x )  dx`


Evaluate the following:

`int ("d"x)/sqrt(16 - 9x^2)`


Evaluate the following:

`int sqrt(x)/(sqrt("a"^3 - x^3)) "d"x`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×